10x^2-40/5x-10

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Solution for 10x^2-40/5x-10 equation: 


x in (-oo:+oo)

10*x^2-((40/5)*x)-10 = 0

10*x^2-8*x-10 = 0

10*x^2-8*x-10 = 0

DELTA = (-8)^2-(-10*4*10)

DELTA = 464

DELTA > 0

x = (464^(1/2)+8)/(2*10) or x = (8-464^(1/2))/(2*10)

x = (4*29^(1/2)+8)/20 or x = (8-4*29^(1/2))/20

x in { (8-4*29^(1/2))/20, (4*29^(1/2)+8)/20 }

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